I have a date column and the data I am loading is something like:
Wed Mar 21 12:45:14 EST 2001
so, how do I load the date with the "EST" and everything.
I know if I were to convert SYSDATE I would do something like:
select to_char(sysdate, 'Dy Month DD HH24:MI:SS "EST" YYYY') from dual;
My MAIN problem is the "EST" thing.
But, in SQL*Loader, I am confused how to tell it to see the date. The documentation regarding this is very confusing.
I have been changing my controlfile around.
My controlfile right now is:
INTO table app_ticker_price
FIELDS terminated by ","
Ticker enclosed by '"',
EquityName enclosed by '"',
Changedate date "DD-MON-YYYY"
thanks for the help.
Well, maybe if I put it another way:
if I do this on my Solaris box:
Wed Mar 21 15:07:54 EST 2001
How does ORACLE covert this to SYSDATE formula?
How does it ignore/erase the "EST"???
jgmagnus the date in solaris has nothing to do the sysdate in oracle if I am correct?
BTW in Metalink someone asked how to convert sysdate to GMT
the suggestion were
use NEW_TIME function
select to_char( NEW_TIME( to_date ('1206212000', 'MMDDHH24YYYY'), 'GMT','EST'), 'dd/mm/yyyy hh:mi:ss') from dual;
But from 8.1.5 upwards only
You can also have a look at this paper
Thanks for replying Pando.
As I understood it, ORACLE gets it's date/time from the server it is installed on (Solaris in this case). So, if I change the server time-stamp by one hour, the Oracle sysdate time will be off by that same hour. That has been my understanding/experience.
Now, HOW Oracle converts the "date" parameter on the server-side into sysdate, I have no idea.
I'll check the link you gave me.
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