
Combine columns from two select statements to one output table (join not possible!)
Combine columns from two select statements to one table
1. statement
Select Sum (Brutto) as B1, Sum (Netto) as N1
FROM Table 1
where ORDER_DATE between '19.09.11' and '19.12.11'
2. statement
Select Sum (Brutto) as B2, Sum (Netto) as N2
FROM Table 1
where ORDER_DATE > trunc(add_months(sysdate,3))
Example for output statement 1
B1 N1
1658,89 1522,12
Example output statement 2
B2 N2
3256,45 2358,56
Question: how to combine both statements into one output?
B1 N1 B2 N2
1658,89 1522,12 3256,45 2358,56
Note: the two resulting tables do not have a column in common; thus one cannot use use a join  correct?
Thanks for your help!

Possible Solution
Select t1.B1, t1.N1, t2.B2, t2.N2
From
(Select Sum (Brutto) as B1, Sum (Netto) as N1
FROM Table 1
where ORDER_DATE between '19.09.11' and '19.12.11') t1
,
(Select Sum (Brutto) as B2, Sum (Netto) as N2
FROM Table 1
where ORDER_DATE > trunc(add_months(sysdate,3))) t2

If you are trying to get the rows from both tables,
but the data is different then you want a union all.
Code:
select *
from ( select sum (brutto) as b1, sum (netto) as n1
from table 1
where order_date between '19.09.11' and '19.12.11'
union all
select sum (brutto) as b2, sum (netto) as n2
from table 1
where order_date > trunc(add_months(sysdate,3)))
order by 1;
this space intentionally left blank

different visualisation
Thanks for the response.
Note: the main difference between simply using a comma (1) or union all (2) is visualisation of the resulting table, i.e.
(1) present all four columns from the two resultnig tables side by side (= resulting table with 4 columns and 1 row), while
(2) presents results from one table in one column and results from the second result table in a second column (= resulting table with two columns and two rows).

Hiii Kairos,
Did you happen to find a solution for your query?
I have the same query and need help, could you help me?
Thanks,
Dharini

WITH
query1 as (
Select nvl(Sum (Brutto),0) as B1, nvl(Sum (Netto),0) as N1
FROM Table 1
where ORDER_DATE between '19.09.11' and '19.12.11'
),
query1 as (
Select nvl(Sum (Brutto),0) as B2, nvl(Sum (Netto),) as N2
FROM Table 1
where ORDER_DATE > trunc(add_months(sysdate,3))
)
select B1,N1,B2,N2 from query1, query2;
suppose that in the result always is going to be an element in any result of any query (nvl) and only one row (not using a group by), using a full join is going to give you what you are looking for.

Originally Posted by hujasodu
WITH
query1 as (
Select nvl(Sum (Brutto),0) as B1, nvl(Sum (Netto),0) as N1
FROM Table 1
where ORDER_DATE between '19.09.11' and '19.12.11'
),
query1 as (
Select nvl(Sum (Brutto),0) as B2, nvl(Sum (Netto),) as N2
FROM Table 1
where ORDER_DATE > trunc(add_months(sysdate,3))
)
select B1,N1,B2,N2 from query1, query2;
suppose that in the result always is going to be an element in any result of any query (nvl) and only one row (not using a group by), using a full join is going to give you what you are looking for.
query1 as (
Select nvl(Sum (Brutto),0) as B1, nvl(Sum (Netto),0) as N1
FROM Table 1
where ORDER_DATE between '19.09.11' and '19.12.11'
),
query2 as (  < it was query2.
Select nvl(Sum (Brutto),0) as B2, nvl(Sum (Netto),) as N2
FROM Table 1
where ORDER_DATE > trunc(add_months(sysdate,3))
)
select B1,N1,B2,N2 from query1, query2;
correction
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