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Thread: Ora-01555 Snapshot Too Old

  1. #21
    Join Date
    Jun 2006
    Posts
    259
    Better yet -- Get rid of the select!

    Try just a delete:
    DELETE FROM table_name WHERE DATE='01-JAN-2002';
    commit;

    However, performing a Delete DOES NOT RECLAIM space in the tablespace. You will be able to add to the table where the delete occurred. The space is not released for useage for other tables in the tablespace.
    ---------------------------------------------------------------------------------

    How many rows are in the table?

    OR just do the CTAS approach:

    create table table_copy as select *
    from your_table
    where date > to_date('01-jan-2002');

    ( this will reclaim the space! )
    truncate table your_Table;

    insert into your_table (select * from table_copy);

    Drop table table_copy;

    ******** WARNING ****
    DO NOT SCRIPT THIS. Run it manually.
    Take an export of the table prior to running the commands.
    *********************

  2. #22
    Join Date
    Sep 2005
    Posts
    278
    Can anybody reply me?

    How about partitioning the table if the data is huge and then removing the partiton which contains old data?

  3. #23
    Join Date
    Jun 2006
    Posts
    259
    Quote Originally Posted by tabreaz
    Can anybody reply me?

    How about partitioning the table if the data is huge and then removing the partiton which contains old data?
    1. That is a design change.
    2. There may not be enough space to accomplish the partitioning without first clearing the table.
    3. good idea, requiring thorough application testing: (maybe vendor table etc..)..

  4. #24
    Join Date
    Nov 2000
    Location
    Pittsburgh, PA
    Posts
    4,166
    You can also try this:

    Code:
    SET SERVEROUTPUT ON
    
    BEGIN
       DBMS_OUTPUT.ENABLE(1000000);
       LOOP
          DELETE table_name
           WHERE DATE='01-JAN-2002'
             AND rownum < 10001;
          DBMS_OUTPUT.PUT_LINE( SQL%ROWCOUNT || ' rows deleted!');
          EXIT WHEN SQL%ROWCOUNT = 0;
          COMMIT;
       END LOOP;
       COMMIT;
    END;
    /
    It's not likely to be faster than a straight delete,
    but it should work without getting the snapshot too old error message.

  5. #25
    Join Date
    Nov 2000
    Location
    greenwich.ct.us
    Posts
    9,092
    Quote Originally Posted by ixion
    1. That is a design change.
    why? A table is a table is a table. You'd have to check the query plans, but assuming you picked a decent partitioning key, you're all set.

    2. There may not be enough space to accomplish the partitioning without first clearing the table.
    not true, just exchange partition with the big table. segments stay the same, just the data dictionary is updated.
    3. good idea, requiring thorough application testing: (maybe vendor table etc..)..
    definitely requires testing, although seems like a lot of work just to delete some data.
    Jeff Hunter

  6. #26
    Join Date
    Nov 2000
    Location
    greenwich.ct.us
    Posts
    9,092
    Quote Originally Posted by gandolf989
    You can also try this:

    Code:
    SET SERVEROUTPUT ON
    
    BEGIN
       DBMS_OUTPUT.ENABLE(1000000);
       LOOP
          DELETE table_name
           WHERE DATE='01-JAN-2002'
             AND rownum < 10001;
          DBMS_OUTPUT.PUT_LINE( SQL%ROWCOUNT || ' rows deleted!');
          EXIT WHEN SQL%ROWCOUNT = 0;
          COMMIT;
       END LOOP;
       COMMIT;
    END;
    /
    It's not likely to be faster than a straight delete,
    but it should work without getting the snapshot too old error message.
    This is the second best solution I've seen.
    Jeff Hunter

  7. #27
    Join Date
    Nov 2000
    Location
    Pittsburgh, PA
    Posts
    4,166
    Quote Originally Posted by marist89
    This is the second best solution I've seen.
    Beats getting the second best poker hand at a table.

  8. #28
    Join Date
    Aug 2000
    Posts
    33
    As mentioned in the earlier replies; do have couple of big size rollback segments. Then execute the delete query by filtering the records by date or any numeric values etc... As it claims the table has got a good number of records.. the deletion cause rollback segment population. To maintain the rollback segment without causing the error the data inserting into rollback segment needs to be controlled; this can be possible by filtering the records in the delete statement.

  9. #29
    Join Date
    Nov 2000
    Location
    greenwich.ct.us
    Posts
    9,092
    Quote Originally Posted by helloravi
    As mentioned in the earlier replies; do have couple of big size rollback segments. Then execute the delete query by filtering the records by date or any numeric values etc... As it claims the table has got a good number of records.. the deletion cause rollback segment population. To maintain the rollback segment without causing the error the data inserting into rollback segment needs to be controlled; this can be possible by filtering the records in the delete statement.
    no. You're not getting the ORA-1555 because of the number of deletes, you're getting it because you can't get a consistent view of the data. You have to externalize the loop by using a "calculatable" entity or an endless loop doing deletes in small chunks until there are no records left. These two methods have already been shown.
    Jeff Hunter

  10. #30
    Join Date
    Sep 2005
    Posts
    278
    This block will be helpful, if you have sufficient memory.

    Code:
    declare
    	type tab_type is table of tablename%rowtype;
    	lobj tab_type;
    begin
    	select *
    	bulk collect into lobj
    	from tablename
    	where DATE <> '01-JAN-2002';
    
    	execute immediate 'create table newtable as select * from tablename 
    		where 1 = 2';
    	
    	execute immediate 'drop table tablename';
    
    	forall i in 1..lobj.count
    		insert into newtable
    		values lrtn(i);
    
    	commit;
    end;

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