Determining if a data is an integer or not?
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Thread: Determining if a data is an integer or not?

  1. #1
    Join Date
    May 2002
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    Determining if a data is an integer or not?

    Is there a way in Oracle SQL that I can look at a position of a column and determine if that data is an integer or not?

    The column is defined as a varchar2 and I know I need to subscript into it(second position for 1 byte) but I don't know how to test for 0-9 without coding 0,1,2,3,4,5,6,7,8,9.

    The data would look something like "CJE20020" and I want to include data with non-interger values(i.e. include the amount for this activity since the second position is a "J").

  2. #2
    Join Date
    Aug 2001
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    267
    I am not clear what you want ..
    Extract second char and
    and use any number function to find it is number or not
    If not number it will error out
    example
    select abs(itmid) from ccs_orders where rownum < 2
    *
    ERROR at line 1:
    ORA-01722: invalid number

    If it is number

    SQL> select abs(acweek) from ccs_orders where rownum < 2;

    ABS(ACWEEK)
    -----------
    1
    Raghu

  3. #3
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    do you mean something like ...

    where translate(substr(my_column,2,1),'1234567890','0000000000')) = '0'
    David Aldridge,
    "The Oracle Sponge"

    Senior Manager, Business Intelligence Development
    XM Satellite Radio
    Washington, DC

    Oracle ACE

  4. #4
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    Originally posted by slimdave
    do you mean something like ...

    where translate(substr(my_column,2,1),'1234567890','0000000000')) = '0'
    This might be what I am looking for. I'll give it a shot and see what get. Thank you.

  5. #5
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    Why are you limited to using only SQL? Test for an integer? You could use the mod function. mod (number/1) not equal to zero --> number is not an integer. Create a function, pass in the number.

  6. #6
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    Well to clarify things a bit, I won't be translating anything. I'm just trying to select data where the second position is alphabetical(i.e. a-z) so is there a way I can specify that without actually typing out all the letters in the alphabet?

    I know I could do it with something like .. SUBTR(column-name,2,1) in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' but I'm assuming there some decent class function or something I could use?

  7. #7
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    translate(upper(substr(my_column,2,1)),'QWERTYUIOPASDFGHJKLZXCVBNM','AAAAAAAAAAAAAAAAAAAAAAAAAAA')) = 'A'

    would do it (check the number of A's, not sure i got it right), or you could check for an ascii code BETWEEN two appropriate values.
    David Aldridge,
    "The Oracle Sponge"

    Senior Manager, Business Intelligence Development
    XM Satellite Radio
    Washington, DC

    Oracle ACE

  8. #8
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    Can you tell me what's the purpose of arranging the values "QWERTYUIOPASDFGHJKLZXCVBNM" in that order? I counted the number of A's and there are 27 of them. Suppose to be 26?

  9. #9
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    Jeez, ever look at the keyboard? What is the first letter in the top left corner?

  10. #10
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    That's why I am a junior member....

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