Distinct Date Search on Date with Time

[storinger]

I'm trying to SEARCH for DISTINCT records in the database based upon a date field. For example, I want to group all records for July 26, 2001. Unfortunately the fields contain not only the date, but the time also. So when I run my query...

SELECT DISTINCT settle_dte FROM heloc_tracking WHERE settle_dte > TO_DATE('25.7.2001','DD.MM.YYYY') AND settle_dte < TO_DATE('27.7.2001','DD.MM.YYYY') ORDER BY settle_dte

...I get a result set of four different records with the same date but four different times.

7/26/2001 06:21:54
7/26/2001 08:43:21
7/26/2001 09:25:18
7/26/2001 12:23:08

How can I get the search to only look at the date part of the fields so when I SEARCH for DISTINCT records, I'll only get the one record.

7/26/2001.

Any ideas please?

[chrisrlong]

SELECT DISTINCT trunc(settle_dte) FROM heloc_tracking WHERE settle_dte > TO_DATE('25.7.2001','DD.MM.YYYY') AND settle_dte < TO_DATE('27.7.2001','DD.MM.YYYY') ORDER BY settle_dte

- Chris

[storinger]

I tried to use the trunc() idea, but I got the following error message...

Microsoft OLE DB Provider for Oracle error '80004005'

ORA-01791: not a SELECTed expression

Am I missing something else?

[marist89]

Sounds like an ODBC incompatibility...

[marist89]

If you are running this query multiple times, you can create a view with the TRUNC() function built-in and select from the view...

[chrisrlong]

SELECT DISTINCT trunc(settle_dte) FROM heloc_tracking WHERE settle_dte > TO_DATE('25.7.2001','DD.MM.YYYY') AND settle_dte < TO_DATE('27.7.2001','DD.MM.YYYY') ORDER BY trunc(settle_dte)

Or it could be yelling about the ORDER BY column not matching the SELECT? Wrap both in a trunc() and try again.

- Chris

[storinger]

That worked.

I had to put the trunc() in the output too to get it to work, but it gave me the correct output.

Thanks